Caffeine And Amine Lab Report
In this experiment, I was unable to complete the tests that would suggest isolation success. If the melting point of the experimental caffeine was tested, the experimental melting point would need to be 238o Celsius to be successfully isolated. A melting point lower than this would suggest that the isolate was impure. If a TLC plate was performed on the crude caffeine and the isolate, the crude would have multiple retention factor values while the isolate, if isolated successfully, should only have one retention factor. If an IR spectrum was performed, the spectrum should only show functional groups in caffeine such as amides and amines, and should not include functional groups like phenyls or esters. If the IR spectrum includes functional ... Show more content on Helpwriting.net ...This is different from "just making tea" because the goal is to make the liquid for the centrifuge tubes as concentrated as possible. When making tea for enjoyment and consumption, the tea is in a larger amount of water and is usually only steeped for three to five minutes. Tea for enjoyment is not intended to be extremely concentrated (in fact, most people would dilute the tea if it is too strong). In this experiment, potassium carbonate acts as a base. Potassium carbonate would dissociate into potassium ions (K+) and carbonate ions (CO3 2–). Carbonate ions would undergo acid–base reactions with the tannins, which then allows the tannins to be water soluble. However, this makes the tannins far less soluble in the organic layer, allowing it to separate from that layer after centrifuging. Because caffeine has dipoles, and thus is polar, it is likely to dissolve in methylene chloride because it is also polar. This means that methylene chloride and caffeine would be in the same layer after centrifuging, separating from the inorganic layer. Water in the mixture exists in the inorganic layer and is used to isolate the caffeine from the tannins from the tea
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